Originally Posted by

**Shaula**
No on all counts. First off it is based on something. It is based on theory. Second the value of the cosmological constant changing won't change kappa. That assumption was made to simplify the calculation such that kappa could easily be derived. Kappa is then true for general cases where lambda is not zero.

If I were to write simple code in C, I would have something like this:

Code:

float const pi = 3.1416;
float theory(float G, float c, float lambda)
{
return G/c^2 * 8 * pi;
}
float kappa(float G, float c, float lambda)
{
return theory(G, c, lambda);
}

So what I mean here is that the function theory() is not based on any external variable other than G, c and lambda.

I believe my original question was answered but is it possible to have the derived value of kappa without the simplifications? I never liked "simplifications" because it's a source of error.