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Goldstone
2011-Oct-05, 03:59 PM
There is a situation where there is a problem with current hypothesis with energy ranges consistant with the mass of the Higgs. There and here, we find ourselves fluctuation between an inherent problem of the standard model.

Mathematicians will admit that there is no other solution to the standard (and most simplest) equations to adding mass to a system than that which is found in the solutions for the simple potential of the mexican hat. In this case, a Higgs field should be taken seriously, but the quantization field should be a local phenomenon which expands directly over all minimal particle masses; particles which do not favor that energy level are reserved for the family of exotic particles which make up dark energy.

Without such speculative thoughts, the energy required to shift the equations to allow a symmetry breaking in the mexican hat potential, a simple one at that, allows us to speculate that this symmetry breaking could be allowed by assuming the mass of particle is obtained by borrowing this energy from the gradient gravitational potential field.

Mathematically, a particle with a mass that will depend upon the gravitational field energy locally covariant component of a minkowski four dimensional equation provides us with the description:

http://www.codecogs.com/eq.latex?\bar{\psi}(\Box \phi \ell^3) c^2\psi

This covariant expression is derived from Nordstrom's relationship

http://www.codecogs.com/eq.latex?\box \phi = \frac{M}{V}

thus the relationship to find the local mass intrinsic rest relationship is

http://www.codecogs.com/eq.latex? \frac{M}{V} \ell^3 = M

Thus the relativistic relationship accounting momentum-energy contribution is

http://www.codecogs.com/eq.latex?\bar{\psi}c(\gamma^i \cdot \hat{p})\chi + \bar{\psi}(\Box \phi \ell^3) c^2\psi = \bar{\psi} \gamma^0 (i\hbar \partial_t) \psi

Intuitively, mass implies rationally a rest mass which invokes speeds that exist around the minimal energy

http://www.codecogs.com/eq.latex?(\hbar \omega)^{\frac{1}{2}

This means that

http://www.codecogs.com/eq.latex?\bar{\psi}c(\gamma^i \cdot \hat{p})\chi = c

for massless bosons. For faster than light particles, the superluminal component is

http://www.codecogs.com/eq.latex?\bar{\psi}c(\gamma^i \cdot \hat{p})\chi > c (rest)

Goldstone
2011-Oct-05, 11:07 PM
Since the rest energy can be given as

http://www.codecogs.com/eq.latex?\bar{\psi}c(\gamma^i \cdot \hat{p})\chi < c

as less than http://www.codecogs.com/eq.latex?c then we have assumed that the relativistic squared mass component is http://www.codecogs.com/eq.latex?\(E - p)^2 = M^2. To keep the mass positive obeying

http://www.codecogs.com/eq.latex?\bar{\psi}c(\gamma^i \cdot \hat{p})\chi > c

We keep the Tsao-Mass real as a dynamic in four dimensions concerning momentum.

CrazyJesse
2012-Jan-20, 02:32 PM
I find it puzzling that the post received no reply. Is Goldstone a troll at this point?

PetersCreek
2012-Jan-20, 05:35 PM
Speculating as to whether or not the OP is troll is not appropriate and in this case, the point is moot anyway since he has been banned for multiple rules violations. It's also poor form (and potentially disruptive) to revive a dormant thread only to make a post that doesn't contribute to the discussion.